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(8x^2+4x)-(6x^2-7x=6)
We move all terms to the left:
(8x^2+4x)-(6x^2-7x-(6))=0
We get rid of parentheses
8x^2-6x^2+4x+7x+6=0
We add all the numbers together, and all the variables
2x^2+11x+6=0
a = 2; b = 11; c = +6;
Δ = b2-4ac
Δ = 112-4·2·6
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{73}}{2*2}=\frac{-11-\sqrt{73}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{73}}{2*2}=\frac{-11+\sqrt{73}}{4} $
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